GNU Octave  4.0.0
A high-level interpreted language, primarily intended for numerical computations, mostly compatible with Matlab
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passf4.f
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1  subroutine passf4 (ido,l1,cc,ch,wa1,wa2,wa3)
2  dimension cc(ido,4,l1) ,ch(ido,l1,4) ,
3  1 wa1(1) ,wa2(1) ,wa3(1)
4  if (ido .ne. 2) go to 102
5  do 101 k=1,l1
6  ti1 = cc(2,1,k)-cc(2,3,k)
7  ti2 = cc(2,1,k)+cc(2,3,k)
8  tr4 = cc(2,2,k)-cc(2,4,k)
9  ti3 = cc(2,2,k)+cc(2,4,k)
10  tr1 = cc(1,1,k)-cc(1,3,k)
11  tr2 = cc(1,1,k)+cc(1,3,k)
12  ti4 = cc(1,4,k)-cc(1,2,k)
13  tr3 = cc(1,2,k)+cc(1,4,k)
14  ch(1,k,1) = tr2+tr3
15  ch(1,k,3) = tr2-tr3
16  ch(2,k,1) = ti2+ti3
17  ch(2,k,3) = ti2-ti3
18  ch(1,k,2) = tr1+tr4
19  ch(1,k,4) = tr1-tr4
20  ch(2,k,2) = ti1+ti4
21  ch(2,k,4) = ti1-ti4
22  101 continue
23  return
24  102 do 104 k=1,l1
25  do 103 i=2,ido,2
26  ti1 = cc(i,1,k)-cc(i,3,k)
27  ti2 = cc(i,1,k)+cc(i,3,k)
28  ti3 = cc(i,2,k)+cc(i,4,k)
29  tr4 = cc(i,2,k)-cc(i,4,k)
30  tr1 = cc(i-1,1,k)-cc(i-1,3,k)
31  tr2 = cc(i-1,1,k)+cc(i-1,3,k)
32  ti4 = cc(i-1,4,k)-cc(i-1,2,k)
33  tr3 = cc(i-1,2,k)+cc(i-1,4,k)
34  ch(i-1,k,1) = tr2+tr3
35  cr3 = tr2-tr3
36  ch(i,k,1) = ti2+ti3
37  ci3 = ti2-ti3
38  cr2 = tr1+tr4
39  cr4 = tr1-tr4
40  ci2 = ti1+ti4
41  ci4 = ti1-ti4
42  ch(i-1,k,2) = wa1(i-1)*cr2+wa1(i)*ci2
43  ch(i,k,2) = wa1(i-1)*ci2-wa1(i)*cr2
44  ch(i-1,k,3) = wa2(i-1)*cr3+wa2(i)*ci3
45  ch(i,k,3) = wa2(i-1)*ci3-wa2(i)*cr3
46  ch(i-1,k,4) = wa3(i-1)*cr4+wa3(i)*ci4
47  ch(i,k,4) = wa3(i-1)*ci4-wa3(i)*cr4
48  103 continue
49  104 continue
50  return
51  end
std::string dimension(void) const
subroutine passf4(ido, l1, cc, ch, wa1, wa2, wa3)
Definition: passf4.f:1