dsubsp.f

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00001       SUBROUTINE DSUBSP(NMAX, N, A, B, Z, FTEST, EPS, NDIM, FAIL, IND)
00002       INTEGER NMAX, N, FTEST, NDIM, IND(N)
00003       LOGICAL FAIL
00004       DOUBLE PRECISION A(NMAX,N), B(NMAX,N), Z(NMAX,N), EPS
00005 C*
00006 C* GIVEN THE UPPER TRIANGULAR MATRIX B AND UPPER HESSENBERG MATRIX A
00007 C* WITH 1X1 OR 2X2 DIAGONAL BLOCKS, THIS ROUTINE REORDERS THE DIAGONAL
00008 C* BLOCKS ALONG WITH THEIR GENERALIZED EIGENVALUES BY CONSTRUCTING EQUI-
00009 C* VALENCE TRANSFORMATIONS QT AND ZT. THE ROW TRANSFORMATION ZT IS ALSO
00010 C* PERFORMED ON THE GIVEN (INITIAL) TRANSFORMATION Z (RESULTING FROM A
00011 C* POSSIBLE PREVIOUS STEP OR INITIALIZED WITH THE IDENTITY MATRIX).
00012 C* AFTER REORDERING, THE EIGENVALUES INSIDE THE REGION SPECIFIED BY THE
00013 C* FUNCTION FTEST APPEAR AT THE TOP. IF NDIM IS THEIR NUMBER THEN THE
00014 C* NDIM FIRST COLUMNS OF Z SPAN THE REQUESTED SUBSPACE. DSUBSP REQUIRES
00015 C* THE SUBROUTINE EXCHQZ AND THE INTEGER FUNCTION FTEST WHICH HAS TO BE
00016 C* PROVIDED BY THE USER. THE PARAMETERS IN THE CALLING SEQUENCE ARE :
00017 C* (STARRED PARAMETERS ARE ALTERED BY THE SUBROUTINE)
00018 C*
00019 C*    NMAX     THE FIRST DIMENSION OF A, B AND Z
00020 C*    N        THE ORDER OF A, B AND Z
00021 C*   *A,*B     THE MATRIX PAIR WHOSE BLOCKS ARE TO BE REORDERED.
00022 C*   *Z        UPON RETURN THIS ARRAY IS MULTIPLIED BY THE COLUMN
00023 C*             TRANSFORMATION ZT.
00024 C*    FTEST(LS,ALPHA,BETA,S,P) AN INTEGER FUNCTION DESCRIBING THE
00025 C*             SPECTRUM OF THE DEFLATING SUBSPACE TO BE COMPUTED:
00026 C*             WHEN LS=1 FTEST CHECKS IF ALPHA/BETA IS IN THAT SPECTRUM
00027 C*             WHEN LS=2 FTEST CHECKS IF THE TWO COMPLEX CONJUGATE
00028 C*             ROOTS WITH SUM S AND PRODUCT P ARE IN THAT SPECTRUM
00029 C*             IF THE ANSWER IS POSITIVE, FTEST=1, OTHERWISE FTEST=-1
00030 C*    EPS      THE REQUIRED ABSOLUTE ACCURACY OF THE RESULT
00031 C*   *NDIM     AN INTEGER GIVING THE DIMENSION OF THE COMPUTED
00032 C*             DEFLATING SUBSPACE
00033 C*   *FAIL     A LOGICAL VARIABLE WHICH IS FALSE ON A NORMAL RETURN,
00034 C*             TRUE OTHERWISE (WHEN EXCHQZ FAILS)
00035 C*   *IND      AN INTEGER WORKING ARRAY OF DIMENSION AT LEAST N
00036 C*
00037       INTEGER L, LS, LS1, LS2, L1, LL, NUM, IS, L2I, L2K, I, K, II,
00038      * ISTEP, IFIRST
00039       DOUBLE PRECISION S, P, D, ALPHA, BETA
00040       FAIL = .TRUE.
00041       NDIM = 0
00042       NUM = 0
00043       L = 0
00044       LS = 1
00045 C*** CONSTRUCT ARRAY IND(I) WHERE :
00046 C***     IABS(IND(I)) IS THE SIZE OF THE BLOCK I
00047 C***     SIGN(IND(I)) INDICATES THE LOCATION OF ITS EIGENVALUES
00048 C***                  (AS DETERMINED BY FTEST).
00049 C*** NUM IS THE NUMBER OF ELEMENTS IN THIS ARRAY
00050       DO 30 LL=1,N
00051         L = L + LS
00052         IF (L.GT.N) GO TO 40
00053         L1 = L + 1
00054         IF (L1.GT.N) GO TO 10
00055         IF (A(L1,L).EQ.0.) GO TO 10
00056 C* HERE A 2X2  BLOCK IS CHECKED *
00057         LS = 2
00058         D = B(L,L)*B(L1,L1)
00059         S = (A(L,L)*B(L1,L1)+A(L1,L1)*B(L,L)-A(L1,L)*B(L,L1))/D
00060         P = (A(L,L)*A(L1,L1)-A(L,L1)*A(L1,L))/D
00061         IS = FTEST(LS,ALPHA,BETA,S,P)
00062         GO TO 20
00063 C* HERE A 1X1  BLOCK IS CHECKED *
00064    10   LS = 1
00065         IS = FTEST(LS,A(L,L),B(L,L),S,P)
00066    20   NUM = NUM + 1
00067         IF (IS.EQ.1) NDIM = NDIM + LS
00068         IND(NUM) = LS*IS
00069    30 CONTINUE
00070 C***  REORDER BLOCKS SUCH THAT THOSE WITH POSITIVE VALUE
00071 C***    OF IND(.) APPEAR FIRST.
00072    40 L2I = 1
00073       DO 100 I=1,NUM
00074         IF (IND(I).GT.0) GO TO 90
00075 C* IF A NEGATIVE IND(I) IS ENCOUNTERED, THEN SEARCH FOR THE FIRST
00076 C* POSITIVE IND(K) FOLLOWING ON IT
00077         L2K = L2I
00078         DO 60 K=I,NUM
00079           IF (IND(K).LT.0) GO TO 50
00080           GO TO 70
00081    50     L2K = L2K - IND(K)
00082    60   CONTINUE
00083 C* IF THERE ARE NO POSITIVE INDICES FOLLOWING ON A NEGATIVE ONE
00084 C* THEN STOP
00085         GO TO 110
00086 C* IF A POSITIVE IND(K) FOLLOWS ON A NEGATIVE IND(I) THEN
00087 C* INTERCHANGE BLOCK K BEFORE BLOCK I BY PERFORMING K-I SWAPS
00088    70   ISTEP = K - I
00089         LS2 = IND(K)
00090         L = L2K
00091         DO 80 II=1,ISTEP
00092           IFIRST = K - II
00093           LS1 = -IND(IFIRST)
00094           L = L - LS1
00095           CALL EXCHQZ(NMAX, N, A, B, Z, L, LS1, LS2, EPS, FAIL)
00096           IF (FAIL) RETURN
00097           IND(IFIRST+1) = IND(IFIRST)
00098    80   CONTINUE
00099         IND(I) = LS2
00100    90   L2I = L2I + IND(I)
00101   100 CONTINUE
00102   110 FAIL = .FALSE.
00103       RETURN
00104       END
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